Optimal. Leaf size=386 \[ -\frac {i 2^{-2-n} e^{-i (2 a+c n)-i (2 b+d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (\frac {1}{2} \left (-\frac {2 b}{d}-n\right ),-n;\frac {1}{2} \left (2-\frac {2 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{2 b+d n}+\frac {i 2^{-2-n} e^{i (2 a-c n)+i (2 b-d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (\frac {1}{2} \left (\frac {2 b}{d}-n\right ),-n;\frac {1}{2} \left (2+\frac {2 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{2 b-d n}+\frac {i 2^{-1-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i (c+d x)}\right )^{-n} \, _2F_1\left (-n,-\frac {n}{2};1-\frac {n}{2};-e^{2 i (c+d x)}\right )}{d n} \]
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Rubi [A]
time = 0.49, antiderivative size = 386, normalized size of antiderivative = 1.00, number of steps
used = 11, number of rules used = 7, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.412, Rules used = {4651, 2320,
2057, 371, 2323, 2285, 2283} \begin {gather*} -\frac {i 2^{-n-2} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (\frac {1}{2} \left (-\frac {2 b}{d}-n\right ),-n;\frac {1}{2} \left (-\frac {2 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (-i (2 a+c n)-i x (2 b+d n)+i n (c+d x))}{2 b+d n}+\frac {i 2^{-n-2} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (\frac {1}{2} \left (\frac {2 b}{d}-n\right ),-n;\frac {1}{2} \left (\frac {2 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (i (2 a-c n)+i x (2 b-d n)+i n (c+d x))}{2 b-d n}+\frac {i 2^{-n-1} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i (c+d x)}\right )^{-n} \, _2F_1\left (-n,-\frac {n}{2};1-\frac {n}{2};-e^{2 i (c+d x)}\right )}{d n} \end {gather*}
Antiderivative was successfully verified.
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Rule 371
Rule 2057
Rule 2283
Rule 2285
Rule 2320
Rule 2323
Rule 4651
Rubi steps
\begin {align*} \int \cos ^n(c+d x) \sin ^2(a+b x) \, dx &=2^{-2-n} \int \left (2 \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-e^{-2 i a-2 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-e^{2 i a+2 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \, dx\\ &=-\left (2^{-2-n} \int e^{-2 i a-2 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx\right )-2^{-2-n} \int e^{2 i a+2 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx+2^{-1-n} \int \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx\\ &=-\frac {\left (i 2^{-1-n}\right ) \text {Subst}\left (\int \frac {\left (\frac {1}{x}+x\right )^n}{x} \, dx,x,e^{i (c+d x)}\right )}{d}-\left (2^{-2-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-2 i a-2 i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (2^{-2-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{2 i a+2 i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\\ &=-\left (\left (2^{-2-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i (2 a-c n)+i (2 b-d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\right )-\left (2^{-2-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i (2 a+c n)-i (2 b+d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\frac {\left (i 2^{-1-n} \left (e^{i (c+d x)}\right )^n \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i (c+d x)}\right )^{-n}\right ) \text {Subst}\left (\int x^{-1-n} \left (1+x^2\right )^n \, dx,x,e^{i (c+d x)}\right )}{d}\\ &=-\frac {i 2^{-2-n} \exp (-i (2 a+c n)-i (2 b+d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (\frac {1}{2} \left (-\frac {2 b}{d}-n\right ),-n;\frac {1}{2} \left (2-\frac {2 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{2 b+d n}+\frac {i 2^{-2-n} \exp (i (2 a-c n)+i (2 b-d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (\frac {1}{2} \left (\frac {2 b}{d}-n\right ),-n;\frac {1}{2} \left (2+\frac {2 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{2 b-d n}+\frac {i 2^{-1-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i (c+d x)}\right )^{-n} \, _2F_1\left (-n,-\frac {n}{2};1-\frac {n}{2};-e^{2 i (c+d x)}\right )}{d n}\\ \end {align*}
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Mathematica [A]
time = 2.19, size = 249, normalized size = 0.65 \begin {gather*} -\frac {i 2^{-2-n} e^{-2 i (a+b x)} \left (1+e^{2 i (c+d x)}\right )^{-n} \left (e^{-i (c+d x)} \left (1+e^{2 i (c+d x)}\right )\right )^n \left (d n (-2 b+d n) \, _2F_1\left (-\frac {b}{d}-\frac {n}{2},-n;1-\frac {b}{d}-\frac {n}{2};-e^{2 i (c+d x)}\right )+e^{2 i (a+b x)} (2 b+d n) \left (d e^{2 i (a+b x)} n \, _2F_1\left (\frac {b}{d}-\frac {n}{2},-n;1+\frac {b}{d}-\frac {n}{2};-e^{2 i (c+d x)}\right )+2 (2 b-d n) \, _2F_1\left (-n,-\frac {n}{2};1-\frac {n}{2};-e^{2 i (c+d x)}\right )\right )\right )}{-4 b^2 d n+d^3 n^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.07, size = 0, normalized size = 0.00 \[\int \left (\cos ^{n}\left (d x +c \right )\right ) \left (\sin ^{2}\left (b x +a \right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\cos \left (c+d\,x\right )}^n\,{\sin \left (a+b\,x\right )}^2 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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